首页 > 开发 > JSP > 正文

JSP 中Hibernate实现映射枚举类型

2019-10-27 17:59:03
字体:
来源:转载
供稿:网友

JSP 中Hibernate实现映射枚举类型

问题:

Java BO类Gender是枚举类型,想在数据库中存成字符串格式,如何编写hbm.xml?

public enum Gender{   UNKNOWN("Unknown"),   MALE("Male"),   FEMALE("Female");     private String key;  private Gender(final String key) {   this.key = key;  }  public getGender(String key) {   for (Gender gender : Gender.values()) {    if (key.euqals(gender.getKey()))     return gender;         }   throw new NoSuchElementException(key);  } } 

使用UserType:

public class GenderUserType implements UserType {     private static int[] typeList = { Types.VARCHAR};    /*   * Return the SQL type codes for the columns mapped by this type.   * The codes are defined on <tt>java.sql.Types</tt>. */  /**设置和Gender类的sex属性对应的字段的SQL类型 */   public int[] sqlTypes() {    return typeList;  }   /*The class returned by <tt>nullSafeGet()</tt>.*/  /** 设置GenderUserType所映射的Java类:Gender类 */  public Class returnedClass() {    return Gender.class;   }    /** 指明Gender类是不可变类 */   public boolean isMutable() {    return false;  }   /*  * Return a deep copy of the persistent state, stopping at entities and at  * collections. It is not necessary to copy immutable objects, or null  * values, in which case it is safe to simply return the argument.  */  /** 返回Gender对象的快照,由于Gender类是不可变类, 因此直接将参数代表的Gender对象返回 */   public Object deepCopy(Object value) {    return (Gender)value;   }    /** 比较一个Gender对象是否和它的快照相同 */  public boolean equals(Object x, Object y) {   //由于内存中只可能有两个静态常量Gender实例,    //因此可以直接按内存地址比较    return (x == y);   }   public int hashCode(Object x){     return x.hashCode();   }    /*  * Retrieve an instance of the mapped class from a JDBC resultset. Implementors  * should handle possibility of null values.  */  /** 从JDBC ResultSet中读取key,然后返回相应的Gender实例 */  public Object nullSafeGet(ResultSet rs, String[] names, Object owner)                throws HibernateException, SQLException{     //从ResultSet中读取key    String sex = (String) Hibernate.STRING.nullSafeGet(rs, names[0]);     if (sex == null) { return null; }     //按照性别查找匹配的Gender实例     try {      return Gender.getGender(sex);     }catch (java.util.NoSuchElementException e) {      throw new HibernateException("Bad Gender value: " + sex, e);     }   }   /*  * Write an instance of the mapped class to a prepared statement. Implementors  * should handle possibility of null values.  * A multi-column type should be written to parameters starting from <tt>index</tt>.  */  /** 把Gender对象的key属性添加到JDBC PreparedStatement中 */  public void nullSafeSet(PreparedStatement st, Object value, int index)                  throws HibernateException, SQLException{    String sex = null;    if (value != null)      sex = ((Gender)value).getKey();    Hibernate.String.nullSafeSet(st, sex, index);   }    /*  * Reconstruct an object from the cacheable representation. At the very least this  * method should perform a deep copy if the type is mutable. (optional operation)  */  public Object assemble(Serializable cached, Object owner){    return cached;  }     /*    * Transform the object into its cacheable representation. At the very least this    * method should perform a deep copy if the type is mutable. That may not be enough    * for some implementations, however; for example, associations must be cached as    * identifier values. (optional operation)   */   public Serializable disassemble(Object value) {      return (Serializable)value;    }    /*  * During merge, replace the existing (target) value in the entity we are merging to  * with a new (original) value from the detached entity we are merging. For immutable  * objects, or null values, it is safe to simply return the first parameter. For  * mutable objects, it is safe to return a copy of the first parameter. For objects  * with component values, it might make sense to recursively replace component values.  */  public Object replace(Object original, Object target, Object owner){     return original;   }  } 

然后再hbm.xml中定义映射关系:

<hibernate-mapping package="" default-lazy="true" default-cascade="save-update,merge,persist">   <typedef name="Gender" class="com.alpha.hibernate.GenderUserType">     <property name="gender" type="Gender">         <column name="GENDER" not-null="true">         </column>     </property> 

延伸:

为每个枚举类型定义一个UserType是比较麻烦的,可以定义一个抽象类。

例如扩展下例即可适用于所有保存为index的枚举类型

public abstract class OrdinalEnumUserType<E extends Enum<E>> implements UserType {     protected Class<E> clazz;      protected OrdinalEnumUserType(Class<E> clazz) {     this.clazz = clazz;   }      private static final int[] SQL_TYPES = {Types.NUMERIC};    public int[] sqlTypes() {      return SQL_TYPES;    }      public Class<?> returnedClass() {      return clazz;    }      public E nullSafeGet(ResultSet resultSet, String[] names, Object owner)                 throws HibernateException, SQLException {          //Hibernate.STRING.nullSafeGet(rs, names[0])     int index = resultSet.getInt(names[0]);     E result = null;      if (!resultSet.wasNull()) {        result = clazz.getEnumConstants()[index];      }      return result;    }      public void nullSafeSet(PreparedStatement preparedStatement,      Object value,int index) throws HibernateException, SQLException {      if (null == value) {        preparedStatement.setNull(index, Types.NUMERIC);      } else {        //Hibernate.String.nullSafeSet(st, sex, index);       preparedStatement.setInt(index, ((E)value).ordinal());      }    }      public Object deepCopy(Object value) throws HibernateException{      return value;    }      public boolean isMutable() {      return false;    }      public Object assemble(Serializable cached, Object owner)  throws HibernateException {      return cached;   }     public Serializable disassemble(Object value) throws HibernateException {      return (Serializable)value;    }      public Object replace(Object original, Object target, Object owner) throws HibernateException {      return original;    }    public int hashCode(Object x) throws HibernateException {      return x.hashCode();    }    public boolean equals(Object x, Object y) throws HibernateException {      if (x == y)        return true;      if (null == x || null == y)        return false;      return x.equals(y);    }  } 

感谢阅读,希望能帮助到大家,谢谢大家对本站的


注:相关教程知识阅读请移步到JSP教程频道。
发表评论 共有条评论
用户名: 密码:
验证码: 匿名发表