需求分析:
有二级栏目时一级栏目的Url输出 javascript:; 只有一级栏目就输出链接
问题解答:
判断是否有子栏目,有就输出 javascript:; ,没有子栏目就直接输出一级栏目的链接
{dede:field name=typeid runphp=yes}global $dsql;$row = $dsql->GetOne("select * from `dede_arctype` where reid='@me' and ishidden<>1 order by sortrank asc limit 0,1");if(is_array($row)) @me = 'javascript:;';else @me = GetOneTypeUrlA($dsql->GetOne("select * from `dede_arctype` where id='@me' and ishidden<>1"));{/dede:field}
示范
{dede:channelartlist row=7 typeid=top currentstyle=current}<li><a href="{dede:field name=typeid runphp=yes}global $dsql;$row = $dsql->GetOne("select * from `dede_arctype` where reid='@me' and ishidden<>1 order by sortrank asc limit 0,1");if(is_array($row)) @me = 'javascript:;';else @me = GetOneTypeUrlA($dsql->GetOne("select * from `dede_arctype` where id='@me' and ishidden<>1"));{/dede:field}"><span>{dede:field.typename/}</span>{dede:channel type='son' row=1 noself='yes'}<i class="touch-arrow-down"></i>{/dede:channel}</a>{dede:channel type='son' row=1 noself='yes'}<ul>{/dede:channel}{dede:channel type='son' noself='yes'}<li><a href="[field:typelink/]"><span>[field:typename/]</span></a></li>{/dede:channel}{dede:channel type='son' row=1 noself='yes'}</ul>{/dede:channel}</li>{/dede:channelartlist}
运行后结果如下:
目标实现。
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